https://bitfragment.com/tags/ctf/ Recent content in CTF on BITFRAGMENT Hugo -- gohugo.io en-us <a href="https://creativecommons.org/licenses/by-nc/4.0/" target="_blank" rel="noopener">CC BY-NC 4.0</a> Mon, 03 Aug 2020 00:18:16 +0100 https://bitfragment.com/posts/tryhackme-easy-peasy-room/ Mon, 03 Aug 2020 00:18:16 +0100 https://bitfragment.com/posts/tryhackme-easy-peasy-room/ Before we begin, you can access this room by creating an account with tryhackme.com and browsing to this link to join it, or by simply searching for &ldquo;Easy Peasy&rdquo; under the Hacktivities tab. Scanning &amp; Enumeration Running nmap nmap -sV -sC -p- -oA nmap/all -vv 10.10.190.28 Nmap scan report for 10.10.190.28 Host is up, received syn-ack (0.093s latency). Scanned at 2020-08-03 10:01:19 BST for 208s Not shown: 65528 closed ports Reason: 65528 conn-refused PORT STATE SERVICE REASON VERSION 80/tcp open http syn-ack nginx 1. https://bitfragment.com/posts/ctfs-a-simple-guide-on-python-decoding/ Thu, 30 Jul 2020 18:48:16 +0100 https://bitfragment.com/posts/ctfs-a-simple-guide-on-python-decoding/ Ever since I started playing CTFs I found myself decoding various base flags and whilst some of them were pretty straight forward, occasionally, you will find one that is encoded several times and even using various base encodings in the process. How to decode these with Python easily? Well, all you need is this: import base64 f = open(&#34;b64.txt&#34;, &#34;r&#34;).read() for i in range(0,50): f = base64.b64decode(f) print(f) The idea behind it is very simple: